
Lewis structures, devised by Gilbert N. Lewis, visually represent electron arrangements in molecules. By depicting valence electrons as dots and bonds as lines, Lewis structures predict a molecule's shape and properties based on the octet rule. This rule states that atoms tend to achieve stability by having eight electrons in their outer shell. Lewis structures adhere to this rule, offering a clear picture of chemical bonding.
Antimony hydride, also known as stibine (SbH3), is a colorless gas with a pungent odor. It is composed of one antimony atom bonded to three hydrogen atoms. It is used primarily in semiconductor manufacturing and as a reducing agent in various chemical processes. Its CAS number is 7803-52-3.

Let's dive into drawing the Lewis structure of SbH3:
Step 1: Identify the Central Atom: Antimony (Sb) is the central atom in SbH3 because it's less electronegative than hydrogen.
Step 2: Calculate Total Valence Electrons: Antimony contributes 5 valence electrons, and each hydrogen contributes 1, giving a total of 5 + (3 x 1) = 8 valence electrons.
Step 3: Arrange Electrons Around Atoms: Connect each hydrogen atom to the central antimony atom with a single bond (line) and distribute remaining electrons as lone pairs around the antimony atom.
Step 4: Fulfill the Octet Rule: Ensure each hydrogen atom has 2 electrons (1 bonding pair), and the antimony atom has 8 electrons (2 lone pairs and 3 bonding pairs).
Step 5: Check for Formal Charges: Formal charges may not be necessary as all atoms have achieved the octet rule.
The structure of Antimony hydride comprises a central Antimony atom around which 8 electrons or 4 electron pairs are present and one lone pair, therefore molecular geometry of SbH3 will be trigonal pyramidal. There will be a 109.5-degree angle between the H-Sb-H bonds.

This theory addresses electron repulsion and the need for compounds to adopt stable forms. In SbH3, three sigma bonds form between antimony and hydrogen, with one lone pair on the antimony atom. Although antimony has only four valence orbitals, the Lewis structure suggests four bond pairs, implying the use of sp3 hybridization. This hybridization results in a stable trigonal pyramidal geometry.
The Lewis structure suggests that SbH3 adopts a trigonal pyramidal geometry. In this arrangement, the three hydrogen atoms are symmetrically positioned around the central antimony atom, forming three bond pairs. This geometry minimizes electron-electron repulsion, resulting in a stable configuration.
The orbitals involved, and the bonds produced during the interaction of Antimony and hydrogen molecules will be examined to determine the hybridization of Antimony hydride. 5s, 5px, 5py, 5pz are the orbitals involved. The Antimony atom, which is the central atom in its ground state, will have the 5s25p3 configuration in its formation.
The electron pairs in the 5s and 5p orbitals become unpaired in the excited state, and one of each pair is promoted to the unoccupied 5p orbitals. All four half-filled orbitals (one 5s, three 5p) hybridize now, resulting in the production of four sp3 hybrid orbitals.
The bond angle in SbH3 is approximately 109.5 degrees. This angle arises from the trigonal pyramidal geometry of the molecule, where the three hydrogen atoms are positioned around the central antimony atom, resulting in 109.5-degree bond angles between adjacent hydrogen atoms. The bond length in SbH3 is approximately 179 pm.
| Antimony Hydride (CAS 7803-52-3) | |
| Molecular formula | SbH3 |
| Molecular shape | Trigonal Pyramidal |
| Polarity | Polar |
| Hybridization | sp3 hybridization |
| Bond Angle | 109.5 degrees |
| Bond length | 179 pm |
To determine if a Lewis structure is polar, examine the molecular geometry and bond polarity. In the case of antimony hydride (SbH3), the Lewis structure shows antimony at the center bonded to three hydrogen atoms. SbH3 has a trigonal pyramidal geometry, where the three hydrogen atoms are symmetrically arranged around the antimony atom. The molecule is polar due to the presence of a lone pair on the antimony atom, which creates an uneven distribution of charge.
To calculate the total bond energy of SbH3, first, look up the bond energy for a single antimony-hydrogen (Sb-H) bond, which is approximately 310 kJ/mol. SbH3 has three Sb-H bonds, so you multiply the bond energy of one Sb-H bond by the number of bonds. This gives a total bond energy of 930 kJ/mol for SbH3. This value represents the energy required to break all the Sb-H bonds in one mole of SbH3 molecules.
Bond order is the number of chemical bonds between a pair of atoms. In the Lewis structure of SbH3, each antimony-hydrogen bond is a single bond, so the bond order for each Sb-H bond is 1. If a molecule has resonance structures, bond order is averaged over the different structures, but SbH3 does not have resonance, so the bond order remains 1.
Electron groups in a Lewis structure include both bonding pairs (shared electrons) and lone pairs (non-bonded electrons) around an atom. In SbH3, each antimony atom has four electron groups around it, corresponding to the three Sb-H bonds (three bonding pairs and one lone pair on antimony).
In a Lewis dot structure, the dots represent valence electrons. Each dot corresponds to one valence electron of an atom. In SbH3, antimony is surrounded by three bonding pairs (represented by lines in the Lewis structure) and one lone pair. The dots help visualize how electrons are shared or paired between atoms.
![]() |
![]() |