
Lewis structures, devised by Gilbert N. Lewis, visually represent electron arrangements in molecules. By depicting valence electrons as dots and bonds as lines, Lewis structures predict a molecule's shape and properties based on the octet rule. This rule states that atoms tend to achieve stability by having eight electrons in their outer shell. Lewis structures adhere to this rule, offering a clear picture of chemical bonding.
Hydrogen telluride (H2Te) is a colorless, highly toxic gas composed of one tellurium atom bonded to two hydrogen atoms. It is known for its pungent odor and is primarily used in research and specialized industrial applications due to its reactive nature and potential health hazards. H2Te is a binary compound with a linear molecular geometry.

Let's dive into drawing the Lewis structure of H2Te:
Step 1: Identify the Central Atom: Tellurium (Te) is the central atom in H2Te because it's less electronegative than hydrogen.
Step 2: Calculate Total Valence Electrons: Tellurium contributes 6 valence electrons, and each hydrogen contributes 1, giving a total of 6 + (2 x 1) = 8 valence electrons.
Step 3: Arrange Electrons Around Atoms: Connect each hydrogen atom to the central tellurium atom with a single bond (line) and distribute remaining electrons as lone pairs around the tellurium atom.
Step 4: Fulfill the Octet Rule: Ensure each hydrogen atom has 2 electrons (1 bonding pair), and the tellurium atom has 8 electrons (2 lone pairs and 2 bonding pairs).
Step 5: Check for Formal Charges: Formal charges may not be necessary as all atoms have achieved the octet rule.
The structure of hydrogen telluride comprises a central tellurium atom bonded to two hydrogen atoms via single covalent bonds. Tellurium possesses two lone pairs of electrons, resulting in a bent molecular geometry around the tellurium atom. The bond angle between the H-Te-H bonds is approximately 109.5 degrees, and the Te-H bond length is approximately 0.178 nm (178 pm).

This theory addresses electron repulsion and the need for compounds to adopt stable forms. In H2Te, two sigma bonds form between tellurium and hydrogen, with two lone pairs on the tellurium atom. The Lewis structure suggests that tellurium has six valence electrons, indicating the presence of two bond pairs and two lone pairs. This configuration implies the use of sp3 hybrid orbitals, resulting in a stable bent geometry.
The Lewis structure indicates that H2Te adopts a bent geometry. In this arrangement, the two hydrogen atoms are positioned around the central tellurium atom, forming two bond pairs and two lone pairs. This geometry minimizes electron-electron repulsion, leading to a stable configuration.
The orbitals involved in forming the bonds include the 5s and 5p orbitals of tellurium. In its ground state, tellurium has the configuration of 5s25p?. In the excited state, two electrons from the 5p orbitals remain unpaired, and the 5s orbital is involved in hybridization. The orbitals hybridize to form four sp3 hybrid orbitals, two of which form bonds with hydrogen atoms, resulting in the bent structure.
The bond angle in H2Te is approximately 109.5 degrees, and the bond length for the Te-H bond is approximately 0.178 nm (178 pm).
| Hydrogen Telluride Cas 7783-09-7 | |
| Molecular formula | H2Te |
| Molecular shape | Bent |
| Polarity | polar |
| Hybridization | sp3 hybridization |
| Bond Angle | 109.5 degrees |
| Bond length | 178 pm |
To determine if a Lewis structure is polar, examine the molecular geometry and bond polarity. In the case of hydrogen telluride (H2Te), the Lewis structure shows tellurium at the center bonded to two hydrogen atoms. H2Te has a linear geometry, where the two hydrogen atoms are symmetrically arranged around the tellurium atom. Since the H-Te bonds are polar, and the molecule lacks symmetry, H2Te is a polar molecule.
To calculate the total bond energy of H2Te, first, look up the bond energy for a single tellurium-hydrogen (Te-H) bond, which is approximately 258 kJ/mol. H2Te has two Te-H bonds, so you multiply the bond energy of one Te-H bond by the number of bonds. This gives a total bond energy of 516 kJ/mol for H2Te. This value represents the energy required to break all the Te-H bonds in one mole of H2Te molecules.
Bond order is the number of chemical bonds between a pair of atoms. In the Lewis structure of H2Te, each tellurium-hydrogen bond is a single bond, so the bond order for each Te-H bond is 1. If a molecule has resonance structures, bond order is averaged over the different structures, but H2Te does not have resonance, so the bond order remains 1.
Electron groups in a Lewis structure include both bonding pairs (shared electrons) and lone pairs (non-bonded electrons) around an atom. In H2Te, each tellurium atom has two electron groups around it, corresponding to the two Te-H bonds (two bonding pairs and three lone pairs on tellurium).
In a Lewis dot structure, the dots represent valence electrons. Each dot corresponds to one valence electron of an atom. In H2Te, tellurium is surrounded by two bonding pairs (represented by lines in the Lewis structure) and three pairs of dots (lone pairs) and two bonding pairs with hydrogen. The dots help visualize how electrons are shared or paired between atoms.
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