
Lewis structures, devised by Gilbert N. Lewis, visually represent electron arrangements in molecules. By depicting valence electrons as dots and bonds as lines, Lewis structures predict a molecule's shape and properties based on the octet rule. This rule states that atoms tend to achieve stability by having eight electrons in their outer shell. Lewis structures adhere to this rule, offering a clear picture of chemical bonding.
Dihydrogen phosphate (H2PO4-) is an anion formed when a hydrogen ion (H+) is added to a phosphate (PO4^3-) ion. It is a key component in various biochemical processes and plays a significant role in pH buffering systems. The compound is typically found in solutions and aqueous environments.

Let's dive into drawing the Lewis structure of H2PO4-:
Step 1: Identify the Central Atom: Phosphorus (P) is the central atom in H2PO4- because it's less electronegative than oxygen and hydrogen.

Step 2: Calculate Total Valence Electrons: Phosphorus contributes 5 valence electrons, each oxygen contributes 6, and each hydrogen contributes 1. Therefore, the total valence electrons are 5 + (4 × 6) + (2 × 1) - 1 (negative charge) = 30 valence electrons.
Step 3: Arrange Electrons Around Atoms: Connect each oxygen atom to the central phosphorus atom with a single bond (line) and distribute remaining electrons as lone pairs around each oxygen atom. Hydrogen atoms are connected to two of the oxygen atoms.
Step 4: Fulfill the Octet Rule: Ensure each oxygen atom has 8 electrons (2 lone pairs and 1 bonding pair), and the phosphorus atom has 10 electrons (2 lone pairs and 5 bonding pairs).
Step 5: Check for Formal Charges: Adjust the structure to minimize formal charges. The negative charge can be placed on one of the oxygen atoms to achieve a stable configuration.
The structure of dihydrogen phosphate comprises a central phosphorus atom with four electron pairs (two bonding pairs and two lone pairs). The molecular geometry of H2PO4- will be tetrahedral, with the two hydrogen atoms and four oxygen atoms symmetrically positioned around the central phosphorus atom.

This theory addresses electron repulsion and the need for compounds to adopt stable forms. In H2PO4-, the central phosphorus atom forms single bonds with four oxygen atoms, with additional lone pairs on the oxygen atoms. The Lewis structure suggests that the phosphorus atom uses its 3s and 3p orbitals to form these bonds, adhering to the octet rule and achieving a stable configuration.
The Lewis structure suggests that H2PO4- adopts a tetrahedral geometry. In this arrangement, the four oxygen atoms and hydrogen atoms are symmetrically positioned around the central phosphorus atom, forming four bond pairs. This geometry minimizes electron-electron repulsion, resulting in a stable configuration.
The orbitals involved, and the bonds produced during the interaction of phosphorus and oxygen molecules will be examined to determine the hybridization of dihydrogen phosphate. 3s, 3px, 3py, and 3pz are the orbitals involved. The phosphorus atom, which is the central atom in its ground state, will have the 3s23p3 configuration in its formation.
The electron pairs in the 3s and 3px orbitals become unpaired in the excited state, and one of each pair is promoted to the unoccupied 3py and 3pz orbitals. All four half-filled orbitals (one 3s, two 3p) hybridize now, resulting in the production of four sp3 hybrid orbitals.
The bond angle in H2PO4- is approximately 109.5 degrees. This angle arises from the tetrahedral geometry of the molecule, where the four atoms (four oxygens) are positioned at the vertices of a regular tetrahedron, resulting in 109.5-degree bond angles between adjacent atoms. The bond length in H2PO4- is approximately 163 pm.
| Dihydrogen Phosphate (H2PO4-) | |
| Molecular formula | H2PO4- |
| Molecular shape | Tetrahedral |
| Polarity | Polar |
| Hybridization | sp3 hybridization |
| Bond Angle | 109.5 degrees |
| Bond length | 163 pm |
To determine if a Lewis structure is polar, examine the molecular geometry and bond polarity. In the case of dihydrogen phosphate (H2PO4-), the Lewis structure shows phosphorus at the center bonded to four atoms (two oxygens and two hydrogens). H2PO4- has a tetrahedral geometry, but the presence of lone pairs and the asymmetry in the distribution of charges make it a polar molecule.
To calculate the total bond energy of H2PO4-, first, look up the bond energy for a single phosphorus-oxygen (P-O) bond, which is approximately 360 kJ/mol. H2PO4- has four P-O bonds, so you multiply the bond energy of one P-O bond by the number of bonds. This gives a total bond energy of 1440 kJ/mol for H2PO4-. This value represents the energy required to break all the P-O bonds in one mole of H2PO4- molecules.
Bond order is the number of chemical bonds between a pair of atoms. In the Lewis structure of H2PO4-, each phosphorus-oxygen bond is a single bond, so the bond order for each P-O bond is 1. If a molecule has resonance structures, bond order is averaged over the different structures, but H2PO4- does not have resonance, so the bond order remains 1.
Electron groups in a Lewis structure include both bonding pairs (shared electrons) and lone pairs (non-bonded electrons) around an atom. In H2PO4-, the phosphorus atom has four electron groups around it, corresponding to the four P-O bonds (four bonding pairs and no lone pairs on phosphorus).
In a Lewis dot structure, the dots represent valence electrons. Each dot corresponds to one valence electron of an atom. In H2PO4-, phosphorus is surrounded by four bonding pairs (represented by lines in the Lewis structure) and each oxygen atom is represented by three pairs of dots (lone pairs) and one bonding pair with phosphorus. The dots help visualize how electrons are shared or paired between atoms.
![]() |